x^2+36x-1600=0

Solution for x^2+36x-1600=0 equation:

x^2+36x-1600=0

a = 1; b = 36; c = -1600;
Δ = b2-4ac
Δ = 362-4·1·(-1600)
Δ = 7696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7696}=\sqrt{16*481}=\sqrt{16}*\sqrt{481}=4\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{481}}{2*1}=\frac{-36-4\sqrt{481}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{481}}{2*1}=\frac{-36+4\sqrt{481}}{2}
$